(4x)+2cos^2x=1

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Solution for (4x)+2cos^2x=1 equation:


Simplifying
(4x) + 2cos2x = 1

Reorder the terms:
2cos2x + (4x) = 1

Solving
2cos2x + (4x) = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '(-4x)' to each side of the equation.
2cos2x + (4x) + (-4x) = 1 + (-4x)

Combine like terms: (4x) + (-4x) = 0
2cos2x + 0 = 1 + (-4x)
2cos2x = 1 + (-4x)

Divide each side by '2os2x'.
c = 0.5o-1s-2x-1 + (-2o-1s-2)

Simplifying
c = 0.5o-1s-2x-1 + (-2o-1s-2)

Reorder the terms:
c = (-2o-1s-2) + 0.5o-1s-2x-1

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